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Public Relations => Chit Chat => Topic started by: Jake on March 20, 2019, 10:58:19 AM

Title: If Someone could answer this??
Post by: Jake on March 20, 2019, 10:58:19 AM
1. The roots of the quadratic equation x2 + 2(k +1)x + (2k + 5) = 0 are a andb .
(a) Find the range of values of k for which a andb are real.
(b) Find, in terms of k, the quadratic equation whose roots are (2a +ab ) and
(2b +ab ) .

Please leave your answer below

Thnx
Jake :-)
Title: Re: If Someone could answer this??
Post by: HB on March 20, 2019, 07:15:13 PM
Jake .. the answer is 42 (you need to be a certain age to understand this - ask your Dad )  8)
Title: Re: If Someone could answer this??
Post by: Jake on March 21, 2019, 10:51:57 AM
Quote from: HB on March 20, 2019, 07:15:13 PM
Jake .. the answer is 42 (you need to be a certain age to understand this - ask your Dad )  8)

I don't have to ask my dad HB cos I'm a massive fan of Hitch Hikers guide to the Galaxy and I'v read the book ;-)
Title: Re: If Someone could answer this??
Post by: mito on April 27, 2019, 02:17:33 PM
 x2 + 2(k +1)x + (2k + 5) = 0

roots of a quadratic equation, which is defined like this ax2+bx+c = 0 are x1 and x2. By the formula for the roots
x1 = [-b + sqrt(b^2-4ac)]/2a, x2 = [-b - sqrt(b^2-4ac)]/2a. The equation has real roots, if D = b^2-4ac is  >= 0.
So all you have to do is replace the coeficients of the equation to the formula and solve the inequality...
Title: Re: If Someone could answer this??
Post by: Yusif on April 27, 2019, 03:41:38 PM
value of k = -1/2
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